\(\ell \alpha \varepsilon^{a} k ^{ b } T ^{ c } n ^{ d } q ^{ e }\)
(A) \(\ell=\sqrt{\frac{L^{-3} \times A^{2} T^{2}}{M^{-1} A^{2} T^{4} L^{-3} M^{1} L^{2} T^{-2} \theta^{-1} \theta}}\)
\(\ell=\sqrt{\frac{1}{L^{2}}}=\frac{1}{L}\)
(B) \(\ell =\sqrt{\frac{\varepsilon k_{B} T}{n q^{2}}}\)
\(=\sqrt{\frac{\left(M^{-1} A^{2} T^{4} L^{-3}\right) M^{1} L^{2} T^{-2} \theta^{-1} \theta}{L^{-3} A^{1} T^{2}}}\)
\(=\sqrt{L^{2}}=L\)
(C) \(\ell=\sqrt{\frac{A^{2} T^{2}}{M^{-1} A^{2} T^{4} L^{-3} L^{-2} M^{1} L^{2} T^{-2} \theta^{-1} \theta}}\)
(D) \(\ell=\sqrt{\frac{ A ^{2} T ^{2}}{ M ^{-1} A ^{2} T ^{4} L^{-3} L ^{-1} M ^{+1} L ^{2} T ^{-2} \theta^{-1} \theta}}\)
\(=\sqrt{L^{2}}= L\)
So, the correct option is (D): \(\ell=\sqrt{\left(\frac{q^{2}}{\operatorname{sn}^{1 / 3} k_{B} T}\right)}\)
Let $ S $ denote the locus of the point of intersection of the pair of lines $$ 4x - 3y = 12\alpha,\quad 4\alpha x + 3\alpha y = 12, $$ where $ \alpha $ varies over the set of non-zero real numbers. Let $ T $ be the tangent to $ S $ passing through the points $ (p, 0) $ and $ (0, q) $, $ q > 0 $, and parallel to the line $ 4x - \frac{3}{\sqrt{2}} y = 0 $.
Then the value of $ pq $ is
Let $ y(x) $ be the solution of the differential equation $$ x^2 \frac{dy}{dx} + xy = x^2 + y^2, \quad x > \frac{1}{e}, $$ satisfying $ y(1) = 0 $. Then the value of $ 2 \cdot \frac{(y(e))^2}{y(e^2)} $ is ________.
Dimensional Analysis is a process which helps verify any formula by the using the principle of homogeneity. Basically dimensions of each term of a dimensional equation on both sides should be the same.
Limitation of Dimensional Analysis: Dimensional analysis does not check for the correctness of value of constants in an equation.
Let us understand this with an example:
Suppose we don’t know the correct formula relation between speed, distance and time,
We don’t know whether
(i) Speed = Distance/Time is correct or
(ii) Speed =Time/Distance.
Now, we can use dimensional analysis to check whether this equation is correct or not.
By reducing both sides of the equation in its fundamental units form, we get
(i) [L][T]-¹ = [L] / [T] (Right)
(ii) [L][T]-¹ = [T] / [L] (Wrong)
From the above example it is evident that the dimensional formula establishes the correctness of an equation.