Given | Value |
Ladder Length (\(L\)) | 30 m |
Angle with Horizontal (\(\theta\)) | 30° |
The problem involves finding the distance from the foot of the ladder to the wall, referred to as the horizontal distance (\(x\)). This forms a right triangle with the wall, ladder, and ground.
Using trigonometry, the cosine of an angle in a right triangle is defined as:
\( \cos(\theta) = \frac{\text{Adjacent}}{\text{Hypotenuse}} \)
Here, the adjacent side is the distance \(x\), and the hypotenuse is the ladder length.
\( \cos(30°) = \frac{x}{30} \)
We know \( \cos(30°) = \frac{\sqrt{3}}{2} \), so:
\( \frac{\sqrt{3}}{2} = \frac{x}{30} \)
Solving for \(x\), we multiply both sides by 30:
\( x = 30 \times \frac{\sqrt{3}}{2} \)
This simplifies to:
\( x = 15\sqrt{3} \)
Therefore, the correct distance between the foot of the ladder and the wall is 15\(\sqrt{3}\) m.