Question

A hydrocarbon containing one double bond gave on reductive ozonolysis, ethanol and propanone. What is the name of the hydrocarbon?

• A. Ethene
• B. Propene
• C. But-1-ene
• D. 2-Methylprop-1-ene

Hint:

In reductive ozonolysis, carefully analyze the carbonyl products to reconstruct the original hydrocarbon.

Answer 1

The Correct Option is D

In reductive ozonolysis, the double bond in the hydrocarbon is cleaved, and oxygen atoms are inserted to form carbonyl compounds. The hydrocarbon provided yields ethanol (\( \text{CH}_3\text{CH}_2\text{OH} \)) and propanone (\( \text{CH}_3\text{COCH}_3 \)). To determine the original hydrocarbon:
Draw the products and combine them by removing oxygen atoms.
Reconnect the resulting fragments to form the hydrocarbon.
The original hydrocarbon is identified as \( \text{2-Methylprop-1-ene} \), which cleaves to give the specified products.
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Final Answer: \[ \boxed{\text{2-Methylprop-1-ene}} \]