Step 1: Concept of center of mass The weight of the bar is uniformly distributed. Since the bar is uniform, the center of mass lies at the midpoint of the bar.
The total weight \( W \) of the bar is supported by two points:
Step 2: Distribution of weight In a symmetric situation like this, the total weight is evenly distributed between the two points of contact.
\[ \text{Weight experienced by the person} = \frac{W}{2}. \]
Final Answer: \( \frac{W}{2} \).
Match List-I with List-II: List-I