The correct answer is B:140
In the first phase,the group finished \(35\%\) of the project by working 7 hours a day for 10 days.
In the second phase,after 10 people left, the remaining people finished the rest of the project in 14 days by working 10 hours a day.
Let's denote the total work required for the project as W.
In the first phase:
Work done=\(0.35 \times W\)
Work rate=\((Number\space{of}\space people) \times (Hours\space per\space day) \times (Days) = N \times 7 \times 10\)
In the second phase:
Work done=\(0.65 \times W (since\space 100\% - 35\% = 65\%\space remains) \)
Work rate=\((Remaining\space number\space of\space people) \times 10 \times 14=(N - 10) \times 10 \times 14 \)
Since work done equals work rate in each phase, we can set up the following equations:
\(0.35 \times W = N \times 7 \times 10 \)
\(0.65 \times W = (N - 10) \times 10 \times 14 \)
Now we can solve for N:
From equation 1: \(W = \frac{(N \times 7 \times 10)}{0.35}\)
From equation 2: \(W = \frac{((N - 10) \times 10 \times 14)}{0.65}\)
Since both expressions are equal to W, we can set them equal to each other:
\(\frac{(N \times 7 \times 10)}{0.35} = \frac{((N - 10) \times 10 \times 14)}{0.65 }\)
Now solve for N:
\((N \times 7 \times 10 \times 0.65) = ((N - 10) \times 10 \times 14 \times 0.35) \)
Simplify:
\(7 \times 10 \times 0.65 \times N = 10 \times 14 \times 0.35 \times (N - 10) \)
Now solve for N:
\(4.55 \times N = 4.9 \times (N - 10) \)
Distribute on the right side:
\(4.55 \times N = 4.9 \times (N - 49) \)
Subtract \(4.55 \times N\) from both sides:
\(0.35 \times N = 49 \)
Now solve for N:
\(N = \frac{49}{0.35} \)
N=140
So,the initial number of people in the group (N) is 140.