| List I | List II |
| (A) Probability of yellow marble | (I) \(\frac{1}{3}\) |
| (B) Probability of green marble | (II)\(\frac{7}{10}\) |
| (C) Probability of either green or yellow marble | (III) \(\frac{1}{2}\) |
| (D) Probability of either red or yellow marble | (IV) \(\frac{4}{10}\) |
(A)-(II), (B)-(III), (C)-(IV), (D)-(1)
Total number of marbles = \( 1 + 3 + 2 + 4 = 10 \).
Thus, the correct matches are: (C)-(IV), (B)-(I), (C)-(II), (D)-(III).
Four students of class XII are given a problem to solve independently. Their respective chances of solving the problem are: \[ \frac{1}{2},\quad \frac{1}{3},\quad \frac{2}{3},\quad \frac{1}{5} \] Find the probability that at most one of them will solve the problem.