Question:

A gas has a compressibility factor of 0.5 and a molar volume of 0.4 dm3 molβˆ’1 at a temperature of 800K and pressure x atm. If it shows ideal gas behavior at the same temperature and pressure, the molar volume will be y dm3 molβˆ’1. The value of \(\frac{x}{y}\) is ___. [Use: Gas constant, R = 8 Γ— 10βˆ’2 L atm Kβˆ’1 molβˆ’1]

Updated On: July 22, 2025
Hide Solution
collegedunia
Verified By Collegedunia

Correct Answer: 100

Solution and Explanation

Compressibility Factor and Pressure Calculation 

The compressibility factor \( Z \) is given by: \[ Z = \frac{V_{\text{real}}}{V_{\text{ideal}}} = 0.5 \]

The real volume \( V_{\text{real}} \) is: \[ V_{\text{real}} = 0.4 \, \text{dm}^3 \, \text{mol}^{-1} = 0.4 \, \text{L/mol} \]

Using the equation for ideal volume: \[ V_{\text{ideal}} = \frac{0.4}{0.5} = 0.8 \, \text{L/mol} \]

Therefore, \( y = 0.8 \, \text{L/mol} \).

Using the ideal gas law, \( PV = nRT \), we calculate the pressure \( P \): \[ P = \frac{1 \times 8 \times 10^{-2} \times 800}{0.8} \]

Solving for \( P \), we get \( P = 80 \, \text{atm} \).

Finally, the ratio \( \frac{x}{y} \) is: \[ \frac{x}{y} = \frac{80}{0.8} = 100 \]

Was this answer helpful?
0
0

Top Questions on Equilibrium

View More Questions

Questions Asked in JEE Advanced exam

View More Questions

JEE Advanced Notification

Concepts Used:

Equilibrium Constant

The equilibrium constant may be defined as the ratio between the product of the molar concentrations of the products to that of the product of the molar concentrations of the reactants with each concentration term raised to a power equal to the stoichiometric coefficient in the balanced chemical reaction.

The equilibrium constant at a given temperature is the ratio of the rate constant of forwarding and backward reactions.

Equilibrium Constant Formula:

Kequ = kf/kb = [C]c [D]d/[A]a [B]b = Kc

where Kc, indicates the equilibrium constant measured in moles per litre.

For reactions involving gases: The equilibrium constant formula, in terms of partial pressure will be:

Kequ = kf/kb = [[pC]c [pD]d]/[[pA]a [pB]b] = Kp

Where Kp indicates the equilibrium constant formula in terms of partial pressures.

  • Larger Kc/Kp values indicate higher product formation and higher percentage conversion.
  • Lower Kc/Kp values indicate lower product formation and lower percentage conversion.

Medium Kc/Kp values indicate optimum product formation.

Units of Equilibrium Constant:

The equilibrium constant is the ratio of the concentrations raised to the stoichiometric coefficients. Therefore, the unit of the equilibrium constant = [Mole L-1]β–³n.

where, βˆ†n = sum of stoichiometric coefficients of products – a sum of stoichiometric coefficients of reactants.