Question:

A fully charged capacitor 'C' with initial charge 'q0' is connected to a coil of self inductance 'L' at t = 0. The time at which the energy is stored equally between the electric field and the magnetic field is

Updated On: Apr 1, 2025
  • \(\pi \sqrt{LC}\)
  • \(2\pi \sqrt{LC}\)
  • \(\frac{\pi}{4} \sqrt{LC}\)
  • \(\sqrt{LC}\)
Hide Solution
collegedunia
Verified By Collegedunia

The Correct Option is C

Solution and Explanation

A fully charged capacitor \(C\) with an initial charge \(q_0\) is connected to a coil of self-inductance \(L\) at time \(t = 0\). We want to find the time \(t\) at which the energy stored in the electric field of the capacitor is equal to the energy stored in the magnetic field of the inductor.

In an LC circuit, the charge on the capacitor oscillates sinusoidally. The charge \(q(t)\) on the capacitor as a function of time is given by:

\(q(t) = q_0 \cos(\omega t)\)

Where \(\omega\) is the angular frequency of oscillation, and \(\omega = \frac{1}{\sqrt{LC}}\). 

The energy stored in the capacitor at time \(t\) is:

\(U_C = \frac{q(t)^2}{2C} = \frac{q_0^2 \cos^2(\omega t)}{2C}\)

The current \(i(t)\) in the inductor is the derivative of the charge with respect to time:

\(i(t) = \frac{dq(t)}{dt} = -q_0 \omega \sin(\omega t)\)

The energy stored in the inductor at time \(t\) is:

\(U_L = \frac{1}{2}Li(t)^2 = \frac{1}{2}L(-q_0 \omega \sin(\omega t))^2 = \frac{1}{2}Lq_0^2 \omega^2 \sin^2(\omega t)\)

Since \(\omega = \frac{1}{\sqrt{LC}}\), then \(\omega^2 = \frac{1}{LC}\), and we can rewrite the inductor energy as:

\(U_L = \frac{1}{2}Lq_0^2 \frac{1}{LC} \sin^2(\omega t) = \frac{q_0^2 \sin^2(\omega t)}{2C}\)

We want to find the time \(t\) when \(U_C = U_L\). Therefore:

\(\frac{q_0^2 \cos^2(\omega t)}{2C} = \frac{q_0^2 \sin^2(\omega t)}{2C}\)

This implies \(\cos^2(\omega t) = \sin^2(\omega t)\), which means \(\tan^2(\omega t) = 1\), or \(\tan(\omega t) = \pm 1\).

The first positive solution for \(\omega t\) is \(\omega t = \frac{\pi}{4}\). Therefore:

\(t = \frac{\pi}{4\omega} = \frac{\pi}{4 \times \frac{1}{\sqrt{LC}}} = \frac{\pi}{4} \sqrt{LC}\)

Therefore, the time at which the energy is stored equally between the electric field and the magnetic field is:

\(\frac{\pi}{4} \sqrt{LC}\)

Was this answer helpful?
0
0

Top Questions on Electromagnetic induction

View More Questions