Question:

A frictionless wire AB is fixed on a sphere of radius R. A very small spherical ball slips on this wire. The time taken by this ball to slip from A to B is

Updated On: Jun 7, 2022
  • $\frac{\sqrt{2gR}}{g\,cos\,\theta}$
  • $2\sqrt{gR}. \frac{cos\,\theta}{g}$
  • $2\sqrt{\frac{R}{g}}$
  • $\frac{gR}{\sqrt{g\,cos\,\theta}}$
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The Correct Option is C

Solution and Explanation

Acceleration of body along AB is g cos ? Distance travelled in time t sec is
AB $=\frac{1}{2}$ (g cos ?)t

From ?ABC, AB = 2R cos ?
Thus, 2 R cos ? $\frac{1}{2}$ g cos ? t
$\Rightarrow t^{2}=\frac{4\,R}{g} \Rightarrow t=2\sqrt{\frac{R}{g}}$
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