Question:

A force digital transducer measures the pressure in the range of 0-200 N with a resolution of 0.1% of full scale. The smallest charge it can measure is:

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To calculate the smallest measurable change, multiply the full scale by the resolution percentage. In this case, 0.1% of 200 N is 0.2 N.
Updated On: Jun 24, 2025
  • 0.2 N
  • 0.4 N
  • 0.5 N
  • 1.0 N
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The Correct Option is A

Solution and Explanation

The resolution of a digital transducer refers to the smallest change in input that can be detected by the sensor.
The resolution is given as 0.1% of the full scale, where the full scale is 200 N. Thus, the smallest measurable change is: \[ \text{Resolution} = 0.1% \times 200 \, \text{N} = \frac{0.1}{100} \times 200 = 0.2 \, \text{N} \] Therefore, the smallest charge the transducer can measure is 0.2 N.
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