Question

A force digital transducer measures the pressure in the range of 0-200 N with a resolution of 0.1% of full scale. The smallest charge it can measure is:

• A. 0.2 N
• B. 0.4 N
• C. 0.5 N
• D. 1.0 N

Hint:

To calculate the smallest measurable change, multiply the full scale by the resolution percentage. In this case, 0.1% of 200 N is 0.2 N.

Answer 1

The Correct Option is A

The resolution of a digital transducer refers to the smallest change in input that can be detected by the sensor.
The resolution is given as 0.1% of the full scale, where the full scale is 200 N. Thus, the smallest measurable change is: \[ \text{Resolution} = 0.1% \times 200 \, \text{N} = \frac{0.1}{100} \times 200 = 0.2 \, \text{N} \] Therefore, the smallest charge the transducer can measure is 0.2 N.