A flask contains argon and oxygen in the ratio of 3 : 2 in mass and the mixture is kept at 27°C. The ratio of their average kinetic energy per molecule respectively will be
- 3 : 2
- 9 : 4
- 2 : 3
- 1 : 1
The Correct Option is D
Solution and Explanation
The correct answer is (D): 1 : 1
\(KE_{avg}\) = \(\frac{3}{2}\) \(KT\) ( At Lower temperature )
As temperature is same for both the gases.
⇒ Both gases will have same average kinetic energy.
⇒ \(\frac{(KE_{avg})_{argon}}{(KE_{avg})_{oxygen}}\) = \(\frac{1}{1}\)
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Concepts Used:
Kinetic energy
Kinetic energy of an object is the measure of the work it does as a result of its motion. Kinetic energy is the type of energy that an object or particle has as a result of its movement. When an object is subjected to a net force, it accelerates and gains kinetic energy as a result. Kinetic energy is a property of a moving object or particle defined by both its mass and its velocity. Any combination of motions is possible, including translation (moving along a route from one spot to another), rotation around an axis, vibration, and any combination of motions.
