The production function is:
\[ Q = 2\sqrt{L K} \]
For \( Q = 10 \), we set:
\[ 10 = 2\sqrt{L K} \Rightarrow 5 = \sqrt{L K} \]
Squaring both sides:
\[ L K = 25 \]
Let \( L = x \) and \( K = \frac{25}{x} \), then the cost function is:
\[ C = 4L + 16K = 4x + 16 \times \frac{25}{x} \]
Simplifying:
\[ C = 4x + \frac{400}{x} \]
Differentiate \( C \) with respect to \( x \) and set it to zero:
\[ \frac{dC}{dx} = 4 - \frac{400}{x^2} = 0 \]
Solving for \( x \):
\[ 4 = \frac{400}{x^2} \Rightarrow x^2 = 100 \Rightarrow x = 10 \]
Substituting \( x = 10 \) into the cost function:
\[ C = 4(10) + 16 \times \frac{25}{10} \]
\[ C = 40 + 40 = 80 \]
The minimum cost is 80.