Step 1: Understand the fin boundary conditions.
A fin of length \( L \) is analyzed under three boundary conditions at the tip:
Very long fin (infinitely long): The fin is assumed to be so long that the tip temperature approaches the surrounding temperature \( T_\infty \).
Adiabatic tip: The fin tip has no heat transfer (\( q = 0 \)), meaning the temperature gradient at the tip is zero.
Finite convective tip: The fin tip loses heat to the surroundings via convection, with a heat transfer coefficient \( h \).
The base of the fin is at temperature \( T_b \), and the surrounding temperature is \( T_\infty \), where \( T_b>T_\infty \). We need to compare the tip temperatures under these conditions.
Step 2: Derive the tip temperatures for each case.
The general temperature distribution in a fin is governed by the fin equation:
\[
\frac{d^2 \theta}{dx^2} - m^2 \theta = 0,
\]
where \( \theta = T - T_\infty \), \( m = \sqrt{\frac{hP}{kA}} \), \( h \) is the convective heat transfer coefficient, \( P \) is the perimeter, \( k \) is the thermal conductivity, and \( A \) is the cross-sectional area. The boundary condition at the base (\( x = 0 \)) is \( \theta(0) = T_b - T_\infty = \theta_b \).
Very long fin:
For an infinitely long fin, the temperature at the tip (\( x \to \infty \)) approaches the surrounding temperature:
\[
\theta(x) = \theta_b e^{-mx},
\]
\[
T(x \to \infty) = T_\infty,
\]
\[
T_{\text{very long}} = T_\infty.
\]
Adiabatic tip:
The boundary condition at the tip (\( x = L \)) is \( \frac{d\theta}{dx} = 0 \). The solution is:
\[
\theta(x) = \theta_b \frac{\cosh[m(L - x)]}{\cosh(mL)},
\]
At the tip (\( x = L \)):
\[
\theta(L) = \theta_b \frac{\cosh(0)}{\cosh(mL)} = \theta_b \frac{1}{\cosh(mL)},
\]
\[
T_{\text{adiabatic tip}} = T_\infty + (T_b - T_\infty) \frac{1}{\cosh(mL)}.
\]
Since \( \cosh(mL)>1 \), the tip temperature is higher than \( T_\infty \).
Finite convective tip:
The boundary condition at the tip is convective heat loss: \( -k \frac{d\theta}{dx} \bigg|_{x=L} = h \theta(L) \). The solution is more complex, but the tip temperature lies between the adiabatic and very long cases:
\[
\theta(x) = \theta_b \frac{\cosh[m(L - x)] + \frac{h}{mk} \sinh[m(L - x)]}{\cosh(mL) + \frac{h}{mk} \sinh(mL)},
\]
At the tip (\( x = L \)):
\[
\theta(L) = \theta_b \frac{1}{\cosh(mL) + \frac{h}{mk} \sinh(mL)},
\]
\[
T_{\text{convective tip}} = T_\infty + (T_b - T_\infty) \frac{1}{\cosh(mL) + \frac{h}{mk} \sinh(mL)}.
\]
The denominator is larger than in the adiabatic case due to the additional \( \frac{h}{mk} \sinh(mL) \) term, so \( T_{\text{convective tip}}<T_{\text{adiabatic tip}} \), but still greater than \( T_\infty \).
Step 3: Compare the tip temperatures.
\( T_{\text{very long}} = T_\infty \),
\( T_{\text{adiabatic tip}} = T_\infty + (T_b - T_\infty) \frac{1}{\cosh(mL)} \),
\( T_{\text{convective tip}} = T_\infty + (T_b - T_\infty) \frac{1}{\cosh(mL) + \frac{h}{mk} \sinh(mL)} \).
Since \( \cosh(mL) + \frac{h}{mk} \sinh(mL)>\cosh(mL) \), the convective tip temperature is lower than the adiabatic tip but higher than the very long fin:
\[
T_{\text{very long}}<T_{\text{convective tip}}<T_{\text{adiabatic tip}}.
\]
Step 4: Select the correct answer.
The correct observation is \( T_{\text{very long}}<T_{\text{convective tip}}<T_{\text{adiabatic tip}} \), matching option (2).