Question

A fair coin is tossed 3 times in succession. The probability of the event that ‘both first and second toss result in head’ is (rounded off to two decimal places).

Hint:

For independent events, the probability of both occurring is the product of the individual probabilities.

Answer 1

A fair coin has two outcomes: heads (H) and tails (T), each with a probability of 0.5.
We are asked to find the probability that both the first and second toss result in heads.
Step 1: The probability of getting heads on the first toss is: \[ P(\text{First toss heads}) = \frac{1}{2} \] Step 2: The probability of getting heads on the second toss is: \[ P(\text{Second toss heads}) = \frac{1}{2} \] Step 3: The tosses are independent, so the combined probability of both the first and second toss resulting in heads is: \[ P(\text{First toss heads and Second toss heads}) = \frac{1}{2} \times \frac{1}{2} = \frac{1}{4} = 0.25 \] Thus, the probability of the event is 0.25. Final Answer: \[ \boxed{0.25} \]