A drug suspension decomposes by zero-order kinetics with a rate constant of $2 \, \text{mg} \, \text{mL}^{-1} \, \text{month}^{-1}$. If the initial concentration is $100 \, \text{mg} \, \text{mL}^{-1}$, what is the shelf life ($t_{10\%}$)?

Question

cdquestions Admin · Accepted Answer

Step 1: Understanding zero-order kinetics. - The formula for zero-order shelf life ($ t_{10\%} $) is: $$ t_{10\%} = \frac{0.1 C_0}{k} $$ where: - $ C_0 = 100 \, \text{mg} \, \text{mL}^{-1} $ (initial concentration), - $ k = 2 \, \text{mg} \, \text{mL}^{-1} \, \text{month}^{-1} $.  Step 2: Substituting values. $$ t_{10\%} = \frac{0.1 \times 100}{2} = \frac{10}{2} = 5 \, \text{months} $$  Step 3: Correcting for shelf life definition. - The correct formula is: $$ t_{10\%} = \frac{0.1 C_0}{k} = \frac{10}{2} = 5 \, \text{months} $$

Answer

<div>2 months <br></div>

Answer

<div>3 months <br></div>

Answer

<div>4 months <br></div>

Answer

<p>5 months <br> </p>

A drug suspension decomposes by zero-order kinetics with a rate constant of \(2 \, \text{mg} \, \text{mL}^{-1} \, \text{month}^{-1}\). If the initial concentration is \(100 \, \text{mg} \, \text{mL}^{-1}\), what is the shelf life (\(t_{10\%}\))?

The Correct Option is D

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