Radius of the conical pit, r = \(\frac{3.5}{2}\) m = 1.75 m
Depth of the conical pit, h = 12m
Volume of conical pit = \(\frac{1}{3}\pi\)r²h
= \(\frac{1}{3}\) × \(\frac{22}{7}\) × 1.75 m × 1.75 m × 12 m
= 38.5 m³
= 38.5 × 1 kiloliter's
= 38.5 kl
∴ Capacity of the conical pit is 38.5 kiloliters.
When 3.0g of carbon is burnt in 8.00g oxygen, 11.00g of carbon dioxide is produced. What mass of carbon dioxide will be formed when 3.00g of carbon is burnt in 50.0g of oxygen? Which law of chemical combination will govern your answer?