Radius of the conical pit, r = \(\frac{3.5}{2}\) m = 1.75 m
Depth of the conical pit, h = 12m
Volume of conical pit = \(\frac{1}{3}\pi\)r²h
= \(\frac{1}{3}\) × \(\frac{22}{7}\) × 1.75 m × 1.75 m × 12 m
= 38.5 m³
= 38.5 × 1 kiloliter's
= 38.5 kl
∴ Capacity of the conical pit is 38.5 kiloliters.
A driver of a car travelling at \(52\) \(km \;h^{–1}\) applies the brakes Shade the area on the graph that represents the distance travelled by the car during the period.
Which part of the graph represents uniform motion of the car?