The question asks about the focal length of a concave mirror when it is dipped in a liquid of refractive index \( \mu \). The key concept to understand here is how the properties of a mirror differ from those of a lens regarding the effect of a medium’s refractive index.
Concept:
A mirror forms images by reflecting light rather than refracting it. Thus, the change in the surrounding medium does not affect the focal length of a mirror. The focal length of mirrors remains constant irrespective of the surrounding medium, unlike lenses where the focal length changes when immersed in a different medium.
Explanation:
\(f = \frac{R}{2}\)
Conclusion:
Hence, the correct choice is:
\( f \)
For a given reaction \( R \rightarrow P \), \( t_{1/2} \) is related to \([A_0]\) as given in the table. Given: \( \log 2 = 0.30 \). Which of the following is true?
| \([A]\) (mol/L) | \(t_{1/2}\) (min) |
|---|---|
| 0.100 | 200 |
| 0.025 | 100 |
A. The order of the reaction is \( \frac{1}{2} \).
B. If \( [A_0] \) is 1 M, then \( t_{1/2} \) is \( 200/\sqrt{10} \) min.
C. The order of the reaction changes to 1 if the concentration of reactant changes from 0.100 M to 0.500 M.
D. \( t_{1/2} \) is 800 min for \( [A_0] = 1.6 \) M.