The question asks about the focal length of a concave mirror when it is dipped in a liquid of refractive index \( \mu \). The key concept to understand here is how the properties of a mirror differ from those of a lens regarding the effect of a medium’s refractive index.
Concept:
A mirror forms images by reflecting light rather than refracting it. Thus, the change in the surrounding medium does not affect the focal length of a mirror. The focal length of mirrors remains constant irrespective of the surrounding medium, unlike lenses where the focal length changes when immersed in a different medium.
Explanation:
\(f = \frac{R}{2}\)
Conclusion:
Hence, the correct choice is:
\( f \)
Let $ P_n = \alpha^n + \beta^n $, $ n \in \mathbb{N} $. If $ P_{10} = 123,\ P_9 = 76,\ P_8 = 47 $ and $ P_1 = 1 $, then the quadratic equation having roots $ \alpha $ and $ \frac{1}{\beta} $ is:
An organic compound (X) with molecular formula $\mathrm{C}_{3} \mathrm{H}_{6} \mathrm{O}$ is not readily oxidised. On reduction it gives $\left(\mathrm{C}_{3} \mathrm{H}_{8} \mathrm{O}(\mathrm{Y})\right.$ which reacts with HBr to give a bromide (Z) which is converted to Grignard reagent. This Grignard reagent on reaction with (X) followed by hydrolysis give 2,3-dimethylbutan-2-ol. Compounds (X), (Y) and (Z) respectively are: