To find the number of amino groups in the compound (\( x \)), we need to understand the change in molar mass due to acetylation. Acetylation involves replacing an amino hydrogen atom with an acetyl group (\( \text{CH}_3\text{CO} \)), which adds \( 42 \, \text{g mol}^{-1} \) to the molar mass per amino group modified.
1. Compute the difference in molar mass between the acetylated product and the original compound: \( 192 \, \text{g mol}^{-1} - 108 \, \text{g mol}^{-1} = 84 \, \text{g mol}^{-1} \).
2. Since each acetyl group increases the molar mass by \( 42 \, \text{g mol}^{-1} \), determine the number of acetyl groups added: \( \frac{84 \, \text{g mol}^{-1}}{42 \, \text{g mol}^{-1}} = 2 \) amino groups.
This computed value of 2 fits within the expected range of 2,2, confirming the solution is correct.
Each \(\text{NH}_2\) group increases molecular weight by 42 upon acetylation:
\[ 192 - 108 = 84 \] \[ \frac{84}{42} = 2 \]Thus, the compound \(x\) has:
\[ \text{2 amino groups.} \]

In the given figure, the blocks $A$, $B$ and $C$ weigh $4\,\text{kg}$, $6\,\text{kg}$ and $8\,\text{kg}$ respectively. The coefficient of sliding friction between any two surfaces is $0.5$. The force $\vec{F}$ required to slide the block $C$ with constant speed is ___ N.
(Given: $g = 10\,\text{m s}^{-2}$) 
Two circular discs of radius \(10\) cm each are joined at their centres by a rod, as shown in the figure. The length of the rod is \(30\) cm and its mass is \(600\) g. The mass of each disc is also \(600\) g. If the applied torque between the two discs is \(43\times10^{-7}\) dyne·cm, then the angular acceleration of the system about the given axis \(AB\) is ________ rad s\(^{-2}\).
