Let radius = \( r \), height = \( h \), volume \( V = \pi r^2 h \) is constant.
Surface area \( S = 2\pi r^2 + 2\pi rh \).
Using \( h = \frac{V}{\pi r^2} \) and substituting into surface area, minimize \( S \) using calculus.
After optimization, we get \( h = 2r \), so the ratio \( h : r = 2 : 1 \).