The diameter of the circle is equal to the side of the square.
Diameter = 10 cm
\(r = \frac{\text{Diameter}}{2} = \frac{10 \text{ cm}}{2} = 5 \text{ cm}\)
\(\text{Area of circle} = \pi r^2 = \pi \times 5^2 = 25\pi \text{ cm}^2\)
Area of square = side² = 10² = 100 cm²
Area of the region between the square and the circle:
= Area of square - Area of circle = 100 cm² - 25π cm² = 25(4 - π) cm²
ABCD is a trapezoid where BC is parallel to AD and perpendicular to AB . Kindly note that BC<AD . P is a point on AD such that CPD is an equilateral triangle. Q is a point on BC such that AQ is parallel to PC . If the area of the triangle CPD is 4√3. Find the area of the triangle ABQ.