Statement I:
If radius \( r \) of the circle is known, then the diagonal of the square is \( 2r \). Since diagonal of square is \( s\sqrt{2} \), we get:
\[
s = \frac{2r}{\sqrt{2}} = r\sqrt{2}, \quad \text{Area} = s^2 = 2r^2
\]
Statement II:
If tangent from point 5 cm away is given, and length \( t \) is known, then radius can be found using:
\[
r^2 = 5^2 - t^2 \Rightarrow r = \sqrt{25 - t^2}
\]
Then proceed as in Statement I.
So both statements independently are sufficient.