A circle circumscribes a square. What is the area of the square? [I.] Radius of the circle is given.
[II.] Length of the tangent from a point 5 cm away from the centre of the circle is given.
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Use Pythagoras Theorem for tangents and radius to find geometric quantities.
if the question can be answered with the help of any one statement alone but not by the other statement.
if the question can be answered with the help of either of the statements taken individually.
if the question can be answered with the help of both statements together.
if the question cannot be answered even with the help of both statements together.
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The Correct Option isB
Solution and Explanation
Statement I:
If radius \( r \) of the circle is known, then the diagonal of the square is \( 2r \). Since diagonal of square is \( s\sqrt{2} \), we get:
\[
s = \frac{2r}{\sqrt{2}} = r\sqrt{2}, \quad \text{Area} = s^2 = 2r^2
\]
Statement II:
If tangent from point 5 cm away is given, and length \( t \) is known, then radius can be found using:
\[
r^2 = 5^2 - t^2 \Rightarrow r = \sqrt{25 - t^2}
\]
Then proceed as in Statement I.
So both statements independently are sufficient.