Question:

A cart has mass 2 metric ton and sand of 1 metric ton is inside the cart. Now a force of 10 N is applied on cart and sand starts to leak with rate of 0.5 kg/s. What is the velocity of cart when total sand has come out from the cart ?

Updated On: Aug 13, 2024
  • 13.86 m/s
  • 0.06 m/s
  • 2.81 m/s
  • 18.01 m/s
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The Correct Option is A

Solution and Explanation

Mass of the cart with sand changes then its acceleration also changes. $a=\frac{F}{m}=\frac{F}{m_{0}-\mu t}$ where m is mass of system at time t, $m=m_{0}-\mu t$ $a=\frac{F}{m_{0}-\mu t} \quad $or$\quad \frac{dv}{dt}=\frac{F}{m_{0}-\mu t}$ $\displaystyle \int_0^v$ dv=F$\displaystyle \int_0^t$ $\frac{dt}{m_{0}-\mu t}$ $v=\frac{F}{\mu}in\left(\frac{m_{0}}{m_{0}-\mu t}\right)$ Here F = 10 N; ? = 0.5 kg/s m = 2 metric tone m - ?t = 1 metric tone $\therefore\quad v=\frac{10}{0.5}in\left(2\right)=20\times0.693=13.86 $ m/s
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The laws of motion, which are the keystone of classical mechanics, are three statements that defined the relationships between the forces acting on a body and its motion. They were first disclosed by English physicist and mathematician Isaac Newton.

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