A Carnot's engine can have 100% efficiency if the temperature of the sink is
Show Hint
- 273 K
- 0 K
- 0 °C
- 373 K
The Correct Option is B
Solution and Explanation
To get $\eta = 1$ or 100%, we must have: $\dfrac{T_{\text{sink}}}{T_{\text{source}}} = 0$ ⇒ $T_{\text{sink}} = 0$ K
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