Question:
A car engine has a power of 20 kW and runs for 1 hour. If the thermal efficiency is 40\% and ambient temperature is 300 K, then what is the energy generated by fuel combustion?
A car engine has a power of 20 kW and runs for 1 hour. If the thermal efficiency is 40\% and ambient temperature is 300 K, then what is the energy generated by fuel combustion?
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Fuel energy = Work output / Efficiency, when using engine output and time.
Updated On: May 18, 2025
- 180000 kJ
- 240000 kJ
- 360000 kJ
- 270000 kJ
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The Correct Option is A
Solution and Explanation
Useful output energy = Power × time = \( 20 \times 3600 = 72000 \, \text{KJ} \)
Efficiency \( \eta = \frac{\text{Output}}{\text{Input}} \Rightarrow \text{Input} = \frac{Output}{\eta} = \frac{72000}{0.4} = 180000 \, \text{KJ} \)
Efficiency \( \eta = \frac{\text{Output}}{\text{Input}} \Rightarrow \text{Input} = \frac{Output}{\eta} = \frac{72000}{0.4} = 180000 \, \text{KJ} \)
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