Question:

A capacitor has a capacitance of $ 5 \, \mu\text{F} $ and a potential difference of $ 10 \, \text{V} $ is applied across it. What is the charge on the capacitor?

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Remember: The charge on a capacitor is the product of the capacitance and the potential difference across it.
Updated On: May 2, 2025
  • \( 5 \times 10^{-6} \, \text{C} \)

  • \( 5 \times 10^{-5} \, \text{C} \)

  • \( 5 \times 10^{-7} \, \text{C} \)
  • \( 5 \times 10^{-8} \, \text{C} \)
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The Correct Option is B

Solution and Explanation

Calculate the Charge on the Capacitor

We are given the following data:

  • Capacitance \( C = 5 \, \mu\text{F} = 5 \times 10^{-6} \, \text{F} \)
  • Potential difference \( V = 10 \, \text{V} \)

Step 1: Recall the formula for the charge on the capacitor

The formula is: \[ Q = C \cdot V \]

Step 2: Substitute the given values

\[ Q = 5 \times 10^{-6} \, \text{F} \times 10 \, \text{V} = 5 \times 10^{-5} \, \text{C} \]

Conclusion:

The charge on the capacitor is \( 5 \times 10^{-5} \, \text{C} \).

The correct answer is:

Option 2: \( 5 \times 10^{-5} \, \text{C} \)

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