Question:

A capacitor has a capacitance of $ 5 \, \mu\text{F} $ and a potential difference of $ 10 \, \text{V} $ is applied across it. What is the charge on the capacitor?

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Remember: The charge on a capacitor is the product of the capacitance and the potential difference across it.
Updated On: Apr 22, 2025
  • \( 5 \times 10^{-5} \, \text{C} \)
  • \( 5 \times 10^{-6} \, \text{C} \)
  • \( 5 \times 10^{-7} \, \text{C} \)
  • \( 5 \times 10^{-8} \, \text{C} \)
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The Correct Option is B

Solution and Explanation

Step 1: Use the formula for charge on a capacitor
The charge \( Q \) on a capacitor is given by the formula: \[ Q = C V \] where: 
- \( C \) is the capacitance, 
- \( V \) is the potential difference. 
Step 2: Substitute the given values
Given: 
- Capacitance \( C = 5 \, \mu\text{F} = 5 \times 10^{-6} \, \text{F} \), 
- Potential difference \( V = 10 \, \text{V} \). 
Substitute these values into the formula: \[ Q = 5 \times 10^{-6} \times 10 = 5 \times 10^{-5} \, \text{C} \] 
Answer:
Therefore, the charge on the capacitor is \( 5 \times 10^{-5} \, \text{C} \). So, the correct answer is option (2).

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