Question:

A box has 450 balls, each either white or black, there being as many metallic white balls as metallic black balls. If 40% of the white balls and 50% of the black balls are metallic, then the number of non-metallic balls in the box is

Updated On: Jul 22, 2025
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Correct Answer: 250

Solution and Explanation

Given: 

  • Metallic white balls = 40% of W = 0.40W
  • Metallic black balls = 50% of B = 0.50B
  • Number of metallic white balls = Number of metallic black balls
  • Total number of balls = 450

Step 1: Equating metallic balls

Since metallic white balls = metallic black balls:
\( 0.40W = 0.50B \quad \text{...(i)} \)

Step 2: Total number of balls

\( W + B = 450 \quad \text{...(ii)} \)

Step 3: Express W in terms of B

From equation (i):
\( W = \frac{0.50}{0.40}B = \frac{5}{4}B \quad \text{...(iii)} \)

Step 4: Substitute (iii) in (ii)

\( \frac{5}{4}B + B = 450 \)
\( \Rightarrow \frac{9B}{4} = 450 \)
\( \Rightarrow 9B = 1800 \)
\( \Rightarrow B = 200 \)

Step 5: Find W

\( W = 450 - B = 450 - 200 = 250 \)

Step 6: Calculate metallic and non-metallic balls

  • Metallic white balls = \( 0.40 \times 250 = 100 \)
  • Metallic black balls = \( 0.50 \times 200 = 100 \)
  • Non-metallic white balls = \( 250 - 100 = 150 \)
  • Non-metallic black balls = \( 200 - 100 = 100 \)
  • Total non-metallic balls = 150 + 100 = 250

Final Answer: 250 non-metallic balls

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