The temperature change follows Newton's law of cooling, which is given by: \[ \frac{dT}{dt} = -k(T - T_s) \] where \( T \) is the temperature of the object, \( T_s \) is the surrounding temperature, and \( k \) is the cooling constant. We can use the given temperatures to estimate \( k \) and solve for \( T_s \). From the cooling process, the temperature changes as follows: 1. From 50°C to 40°C, the temperature decreases by 10°C in 5 minutes. 2. From 40°C to 33.33°C, the temperature decreases by 6.67°C in the next 5 minutes. Using the equation of exponential decay for cooling, we can estimate that the surrounding temperature \( T_s \) is 20°C.
Hence, the correct answer is (b).
The standard heat of formation, in kcal/mol, of $Ba^{2+}$ is:
Given: Standard heat of formation of SO₄²⁻(aq) = -216 kcal/mol, standard heat of crystallization of BaSO₄(s) = -4.5 kcal/mol, standard heat of formation of BaSO₄(s) = -349 kcal/mol.
A stream of superheated steam (2 MPa, 300°C) mixes with another stream of superheated steam (2 MPa, 400°C) through a steady-state adiabatic process. The flow rates of the streams are 3 kg/min and 2 kg/min, respectively. This mixture then expands in an adiabatic nozzle to a saturated mixture with quality of 0.77 and 1 kPa. Neglect the velocity at the nozzle entrance and the change in potential energies. The velocity at the nozzle exit (in m/s) is ......... (rounded off to two decimal places).
Use the following data:
At 2 MPa, 300 °C: Specific enthalpy of superheated steam = 3024.2 kJ/kg
At 2 MPa, 400 °C: Specific enthalpy of superheated steam = 3248.4 kJ/kg
At 1 kPa: Specific enthalpy of saturated water = 29.3 kJ/kg
At 1 kPa: Specific enthalpy of saturated vapour = 2513.7 kJ/kg
Which of the following is an octal number equal to decimal number \((896)_{10}\)?