Question:

A body moves $6\,m$ north, $8\,m$ east and $10\,m$ vertically upwards, the resultant displacement from its initial position is

Updated On: Jul 5, 2022
  • $10\sqrt{2}\,m$
  • $10\,m$
  • $\frac{10}{\sqrt{2}}\,m$
  • $20\,m$
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The Correct Option is A

Solution and Explanation

The situation is as shown in the figure
$OC=\sqrt{OA^{2}+AB^{2}+BC^{2}}$ $=\sqrt{6^{2}+8^{2}+10^{2}}$ $=10\sqrt{2}\,m$
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Concepts Used:

Motion in a Plane

It is a vector quantity. A vector quantity is a quantity having both magnitude and direction. Speed is a scalar quantity and it is a quantity having a magnitude only. Motion in a plane is also known as motion in two dimensions. 

Equations of Plane Motion

The equations of motion in a straight line are:

v=u+at

s=ut+½ at2

v2-u2=2as

Where,

  • v = final velocity of the particle
  • u = initial velocity of the particle
  • s = displacement of the particle
  • a = acceleration of the particle
  • t = the time interval in which the particle is in consideration