Question:

A beam of light of wavelength 600 nm from a distant source falls on a single slit I mm wide and the resulting diffraction-pattern is observed on a screen 2m away. The distance between the first dark fringes on either side of the central bright fringe is

Updated On: Apr 19, 2024
  • 1.2 cm
  • 1.2 mm
  • 2.4cm
  • 2.4mm
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The Correct Option is D

Solution and Explanation

$ \beta =\frac{\lambda D}{d}=\frac{600\times {{10}^{-9}}\times 2}{1\times {{10}^{-3}}}=12\times {{10}^{-4}}\,m $ So, distance between the first dark fringes on either side of the central bright fringe $ X=2\beta $ $ =2\times 12\times {{10}^{-4}}m $ $ =24\times {{10}^{-4}}m $ $ =2.4\,mm $
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Concepts Used:

Single Slit Diffraction

In the single-slit diffraction experiment, we can examine the bending phenomenon of light or diffraction that causes light from a coherent source to hinder itself and produce an extraordinary pattern on the screen called the diffraction pattern.

Single Slit Diffraction
The path difference exhibited by the top two rays

 

 

 

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Central Maximum

Central Maximum