At the highest point, the velocity of the ball becomes zero. Using the equation of motion:
\[
v = u + at
\]
Where:
- \( v = 0 \, \text{m/s} \) (velocity at the highest point),
- \( u = 20 \, \text{m/s} \) (initial velocity),
- \( a = -g = -9.8 \, \text{m/s}^2 \) (acceleration due to gravity, acting downward).
Rearranging the equation to solve for time \( t \):
\[
0 = 20 - 9.8 \times t
\]
\[
t = \frac{20}{9.8} = 2.04 \, \text{s}
\]
Thus, the time taken for the ball to reach the highest point is \( 2.04 \, \text{s} \).