Question:

A ball is thrown vertically upwards with an initial velocity of 20 m/s. Calculate the time it takes for the ball to reach the highest point. (Assume \( g = 9.8 \, \text{m/s}^2 \))

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At the highest point, the velocity of a vertically thrown object becomes zero. The time to reach the highest point is simply the time taken for the velocity to reduce to zero under the influence of gravity.
Updated On: Apr 15, 2025
  • \( 2.04 \, \text{s} \)
  • \( 1.8 \, \text{s} \)
  • \( 3.0 \, \text{s} \)
  • \( 4.0 \, \text{s} \)
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The Correct Option is A

Solution and Explanation

At the highest point, the velocity of the ball becomes zero. Using the equation of motion: \[ v = u + at \] Where: - \( v = 0 \, \text{m/s} \) (velocity at the highest point), - \( u = 20 \, \text{m/s} \) (initial velocity), - \( a = -g = -9.8 \, \text{m/s}^2 \) (acceleration due to gravity, acting downward). Rearranging the equation to solve for time \( t \): \[ 0 = 20 - 9.8 \times t \] \[ t = \frac{20}{9.8} = 2.04 \, \text{s} \] Thus, the time taken for the ball to reach the highest point is \( 2.04 \, \text{s} \).
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