Kinetic energy,
\(KE=\frac 12mv^2=E\)
At highest point,
\(KE'=\frac 12mv^2 cos\ 2θ\)
\(=\frac 12mv^2(\frac 14)\)
\(=\frac E4\)
So, the correct option is (C): \(\frac E4\)
A bob of mass \(m\) is suspended at a point \(O\) by a light string of length \(l\) and left to perform vertical motion (circular) as shown in the figure. Initially, by applying horizontal velocity \(v_0\) at the point ‘A’, the string becomes slack when the bob reaches at the point ‘D’. The ratio of the kinetic energy of the bob at the points B and C is: 

Nature of compounds TeO₂ and TeH₂ is___________ and ______________respectively.
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