The bag contains 3 red and 4 blue balls, so the total number of balls is \( 3 + 4 = 7 \).
The probability of drawing a red ball is: \[ P(\text{red}) = \frac{\text{number of red balls}}{\text{total number of balls}} = \frac{3}{7} \] Thus, the probability is: \[ \boxed{\frac{3}{7}} \]
If \(S=\{1,2,....,50\}\), two numbers \(\alpha\) and \(\beta\) are selected at random find the probability that product is divisible by 3 :
If the probability distribution is given by:
| X | 0 | 1 | 2 | 3 | 4 | 5 | 6 | 7 |
|---|---|---|---|---|---|---|---|---|
| P(x) | 0 | k | 2k | 2k | 3k | k² | 2k² | 7k² + k |
Then find: \( P(3 < x \leq 6) \)