Question:

a×b2+a.b2=144|\vec{a}\times\vec{b}|^2+|\vec{a}.\vec{b}|^2=144 and a=4|\vec{a}|=4 then b|\vec{b}| is equal to

Updated On: Apr 17, 2024
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The Correct Option is D

Solution and Explanation

The correct answer is (D) : 4.
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