A and B together can complete a task in 7 days. B alone can do it in 20 days. What part of the work was carried out by A?
Statement I - A completed the job alone after A and B worked together for 5 days.
Statement II - Part of the work done by A could have been done by B and C together in 6 days.
From Statement I:
A and B together can complete the task in 7 days, so their combined rate of work is: \[ \frac{1}{7} { of the work per day}. \] B alone can do it in 20 days, so B’s rate of work is: \[ \frac{1}{20} { of the work per day}. \] Since A and B work together for 5 days, the amount of work completed by both A and B is: \[ 5 \times \left( \frac{1}{7} \right) = \frac{5}{7} \] The remaining work is: \[ 1 - \frac{5}{7} = \frac{2}{7}. \] A then completes the remaining work alone. The rate of work of A is: \[ \frac{1}{7} - \frac{1}{20} = \frac{20 - 7}{140} = \frac{13}{140}. \] The time A takes to complete the remaining work is: \[ \frac{2}{7} \div \frac{13}{140} = \frac{2}{7} \times \frac{140}{13} = \frac{280}{91} = \frac{20}{13} { days}. \] Thus, Statement I alone is sufficient to answer the question.
Which direction is Raju facing at the moment?
Statement I - Raju took 2 consecutive right turns after covering a distance of 6m to reach the point X.
Statement II - After walking 4m early morning from point X, Raju is facing opposite direction of the sun.
Among P, Q, R, S, T, and U, who is the heaviest?
Statement I - P is heavier than T and U and he is the second heaviest in the group.
Statement II - S is heavier than Q but not the heaviest.
A closed-loop system has the characteristic equation given by: $ s^3 + k s^2 + (k+2) s + 3 = 0 $.
For the system to be stable, the value of $ k $ is:
A digital filter with impulse response $ h[n] = 2^n u[n] $ will have a transfer function with a region of convergence.