A and B rent a pasture for 10 months; A puts in 80 cows for 7 months. How many can B put in for the remaining 3 months, if he pays half as much again as A?
To solve the problem, let's first understand the concept of rent based on the number of cows and the time they stay on the pasture. This is known as "Cow-Months". The rent paid is proportional to the number of cow-months utilized.
Since B pays "half as much again" as A, B pays for: \( 1.5 \times 560 = 840 \text{ cow-months} \).
To find the number of cows B can put in for the remaining 3 months, divide the total cow-months for B by the number of months: \( \frac{840 \text{ cow-months}}{3 \text{ months}} = 280 \text{ cows} \).
Therefore, B can put in 280 cows for the remaining 3 months.