

Taking torque from B
\(Fw\times5= \frac{3}{2} \text{ mg}\)
\(\Rightarrow Fw= \frac{3}{10} \times 10 \times 10 = 30 N\)
N = mg = 100 N
and fr = Fw = 30 N
So, Ef=\(\sqrt{N_2+f_r2}\)
Ef = \(\sqrt{10900}\)
Ef = 10\(\sqrt{109}\)
\(\frac{F_r}{F_w}\)=\(\frac{3}{\sqrt{109}}\)
In the given figure, the blocks $A$, $B$ and $C$ weigh $4\,\text{kg}$, $6\,\text{kg}$ and $8\,\text{kg}$ respectively. The coefficient of sliding friction between any two surfaces is $0.5$. The force $\vec{F}$ required to slide the block $C$ with constant speed is ___ N.
(Given: $g = 10\,\text{m s}^{-2}$) 
The equivalent resistance between the points \(A\) and \(B\) in the given circuit is \[ \frac{x}{5}\,\Omega. \] Find the value of \(x\). 
Method used for separation of mixture of products (B and C) obtained in the following reaction is: 
Different types of forces that are found in nature can be broadly categorized into two types:
Contact Forces can further be divided into the following types:
Action-at-a-Distance Force is exerted without the objects being in contact. The various types of Action-at-a-Distance Force are as follows: