Question:

60 kg of an alloy X is mixed with 100 kg of an alloy Y. If alloy X has lead and tin in the ratio of 3:2 and alloy Y has tin and copper in the ratio of 1:4, then the amount of tin in the new alloy is

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When working with alloys, break down the problem into ratios and calculate the individual amounts of components.
Updated On: Aug 18, 2025
  • 53 kgs
  • 80 kgs
  • 36 kgs
  • 44 kgs
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The Correct Option is D

Solution and Explanation

Alloy X contains \( \frac{2}{5} \) of tin as it has a ratio of 3:2 of lead to tin. Thus, the amount of tin in alloy X is: \[ \text{Tin in X} = \frac{2}{5} \times 60 = 24 \, \text{kgs} \] Alloy Y contains \( \frac{1}{5} \) of tin as it has a ratio of 1:4 of tin to copper. Thus, the amount of tin in alloy Y is: \[ \text{Tin in Y} = \frac{1}{5} \times 100 = 20 \, \text{kgs} \] Therefore, the total amount of tin in the new alloy is: \[ \text{Total tin} = 24 \, \text{kgs} + 20 \, \text{kgs} = 44 \, \text{kgs} \] - Option (A) 53 kgs: Incorrect. This is not the correct amount of tin.
- Option (B) 80 kgs: Incorrect. This would suggest a much higher amount of tin.
- Option (C) 36 kgs: Incorrect. This does not align with the math.
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