Question:
34.2% (W/V) sucrose $ \left( \text{C}_6\text{H}_2\text{O}_1\right) $ solution is isotonic with 18% (W/V) of unknown solution X. Formula of X is
34.2% (W/V) sucrose $ \left( \text{C}_6\text{H}_2\text{O}_1\right) $ solution is isotonic with 18% (W/V) of unknown solution X. Formula of X is
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When solving isotonic solution problems, remember that the osmotic pressure of two isotonic solutions is equal.
Updated On: Jan 6, 2026
\(\text{C}_6\text{H}_1\text{O}_4\)
\(\text{C}_6\text{H}_1\text{O}_2\)
$\text{C}_6\text{H}_1\text{O}_6$
$\text{C}_5\text{H}_1\text{O}_5$
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The Correct Option is C
Solution and Explanation
To determine the formula of X, we use the concept of isotonic solutions. Isotonic solutions have the same osmotic pressure.
Thus, we can use the relation between osmotic pressure and molarity to solve this problem. We know that the molarity of a solution is related to the molar mass and the weight fraction of the solute. For the given sucrose solution and the unknown solution X, the molar concentrations of the solutes are equivalent. Using the given data, we can calculate the formula of X to be \(\text{C}_6\text{H}_1\text{O}_6\).
Thus, we can use the relation between osmotic pressure and molarity to solve this problem. We know that the molarity of a solution is related to the molar mass and the weight fraction of the solute. For the given sucrose solution and the unknown solution X, the molar concentrations of the solutes are equivalent. Using the given data, we can calculate the formula of X to be \(\text{C}_6\text{H}_1\text{O}_6\).
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