Question:
\(3\!\begin{bmatrix}7&-2 \\ 8&0\end{bmatrix}=\ \ ?\)
\(3\!\begin{bmatrix}7&-2 \\ 8&0\end{bmatrix}=\ \ ?\)
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A scalar in front of a matrix distributes to every position.
Updated On: Oct 17, 2025
\(\begin{bmatrix}21&-6 \\ 8&0\end{bmatrix}\)
\(\begin{bmatrix}7&-2 \\ 24&0\end{bmatrix}\)
\(\begin{bmatrix}21&-6 \\ 24&0\end{bmatrix}\)
\(\begin{bmatrix}21&-2 \\ 8&0\end{bmatrix}\)
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The Correct Option is C
Solution and Explanation
Multiply each entry by \(3\): \[ 3\!\begin{bmatrix}7&-2 \\ 8&0\end{bmatrix} =\begin{bmatrix}3\times7&3\times(-2) \\ 3\times8&3\times0\end{bmatrix} =\begin{bmatrix}21&-6 \\ 24&0\end{bmatrix}. \]
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