- Initial amount of acetic acid = \(0.5 \, \text{M} \times 100 \, \text{mL} = 0.5 \, \text{mol/L} \times 0.1 \, \text{L} = 0.05 \, \text{mol}\).
- Final amount of acetic acid = \(0.4 \, \text{M} \times 100 \, \text{mL} = 0.4 \, \text{mol/L} \times 0.1 \, \text{L} = 0.04 \, \text{mol}\).
- Amount adsorbed = \(0.05 - 0.04 = 0.01 \, \text{mol}\).
- The amount of acetic acid adsorbed on 2.0 g of charcoal = 0.01 mol.
- Molar mass of acetic acid = 60 g/mol, so the mass adsorbed = \(0.01 \, \text{mol} \times 60 \, \text{g/mol} = 0.6 \, \text{g}\).
- Grams adsorbed per gram of charcoal = \(\frac{0.6 \, \text{g}}{2.0 \, \text{g}} = 0.3\).