Question

\(1s^2, 2s^2, 2p^6, 3s^2, 3p^6\) configuration is related to

• A. \(P ^{–3}\)
• B. \(Cl ^{–}\)
• C. \(S ^{–2}\)
• D. All of these

Answer 1

The Correct Option is D

The electronic configuration provided is \(1s^2, 2s^2, 2p^6, 3s^2, 3p^6\). To understand which ions this configuration corresponds to, we need to evaluate each element's ground state and how gaining electrons affects their configurations.

1. Identify the ground state configuration of each element:

• Phosphorus (\(P\)) has a ground state configuration of \(1s^2, 2s^2, 2p^6, 3s^2, 3p^3\).
• Chlorine (\(Cl\)) has a ground state configuration of \(1s^2, 2s^2, 2p^6, 3s^2, 3p^5\).
• Sulfur (\(S\)) has a ground state configuration of \(1s^2, 2s^2, 2p^6, 3s^2, 3p^4\).

2. Account for gained electrons in ionic forms:

• \(P ^{–3}\) has gained 3 electrons, resulting in \(3p^6\), matching the configuration given (\(1s^2, 2s^2, 2p^6, 3s^2, 3p^6\)).
• \(Cl ^{–}\) has gained 1 electron, resulting also in \(3p^6\), matching the provided configuration.
• \(S ^{–2}\) has gained 2 electrons, resulting in \(3p^6\), similarly fitting the configuration.

3. Conclusion:

Since all these ions \(P ^{–3}, Cl ^{–}, S ^{–2}\) can result in the provided electronic configuration, the correct answer is "All of these".

Answer 2

Correct answer: All of these

Explanation:
The electronic configuration given is: \(1s^2, 2s^2, 2p^6, 3s^2, 3p^6\) This is the configuration of Argon (Ar), a noble gas with atomic number 18.

Let's check each ion:
• Phosphorus (P) has atomic number 15. So, neutral P has: \(1s^2, 2s^2, 2p^6, 3s^2, 3p^3\) → P^–3 gains 3 electrons → \(1s^2, 2s^2, 2p^6, 3s^2, 3p^6\)

• Chlorine (Cl) has atomic number 17. Neutral Cl has: \(1s^2, 2s^2, 2p^6, 3s^2, 3p^5\) → Cl^– gains 1 electron → \(1s^2, 2s^2, 2p^6, 3s^2, 3p^6\)

• Sulfur (S) has atomic number 16. Neutral S has: \(1s^2, 2s^2, 2p^6, 3s^2, 3p^4\) → S^–2 gains 2 electrons → \(1s^2, 2s^2, 2p^6, 3s^2, 3p^6\)

All three ions have the same electronic configuration as Argon.
Hence, the correct answer is: All of these.