Question:

0.5g of non-volatile solute is added to 39g of Benzene. Then vapor pressure of solution is (vapor pressure of pure Benzene is 0.850 torr)

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When calculating vapor pressure depression, use Raoult's Law and remember to consider the molar masses and the mass of the solute and solvent.
Updated On: May 9, 2025
  • 0.845 torr
  • 0.850 torr
  • 0.860 torr
  • 0.870 torr
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The Correct Option is A

Solution and Explanation

The change in vapor pressure due to the addition of a non-volatile solute can be calculated using Raoult's Law:
\[ \Delta P = P_0 - P = \frac{n_{\text{solute}}}{n_{\text{solvent}}} \times P_0 \] Given that \( P_0 = 0.850 \) torr and the amount of solute added is small, the new vapor pressure is:
\[ \text{New vapor pressure} = 0.845 \, \text{torr} \]
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