If conductivity of water used to make saturated of AgCl is found to be \(3.1\times10^{-5}Ω^{-1}cm^{-1}\) and conductance of the solution of AgCl = \(4.5\times10^{-5}Ω^{-1}cm^{-1}\)
If \(λ^θ\) AgNO3 = \(200 Ω^{-1}cm^{2}mole^{-1}\)
\(λ^θ\)NaNO3 = \(310 Ω^{-1}cm^{2}mole^{-1}\)
calculate Ksp of AgCl