The emf of Daniell cell at $298 K$ is $E_{1}$ $Zn \left| ZnSO _{4}(0.01 M )\right|\left| CuSO _{4}(1.0 M )\right| Cu$ When the concentration of $ZnSO _{4}$ is $1.0 M$ and that of $CuSO _{4}$ is $0.01 M$, the emf changed to $E_{2}$. What is the relation between $E_{1}$ and $E_{2}$ ?