Question:

When nitric acid reacts with nitric oxide, a gas is released, which converts $H _{2} S$ into

Updated On: Mar 30, 2023
  • $SO _{4}^{2-}$
  • $S ^{2-}$
  • $S$
  • $S _{2} O _{5}^{2-}$
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The Correct Option is C

Solution and Explanation

When nitric acid $\left( HNO _{3}\right)$ reacts with nitric oxide (NO), $NO _{2}$ gas is released which oxidises $H _{2} S$ into sulphur. The reactions are as follows : $2 HNO _{3}+ NO \longrightarrow H _{2} O +3 NO _{2} $ $NO _{2}+ H _{2} S \longrightarrow H _{2} O + S + NO$
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Concepts Used:

P-Block Elements

  • P block elements are those in which the last electron enters any of the three p-orbitals of their respective shells. Since a p-subshell has three degenerate p-orbitals each of which can accommodate two electrons, therefore in all there are six groups of p-block elements.
  • P block elements are shiny and usually a good conductor of electricity and heat as they have a tendency to lose an electron. You will find some amazing properties of elements in a P-block element like gallium. It’s a metal that can melt in the palm of your hand. Silicon is also one of the most important metalloids of the p-block group as it is an important component of glass.

P block elements consist of: