Question:

Xenon (VI) fluoride on complete hydrolysis gives an oxide of xenon 'O'. The total number of \( \sigma \) and \( \pi \) bonds in 'O' is:

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Xenon trioxide (\( XeO_3 \)) has 3 single bonds (\( \sigma \)) and 3 double bonds (\( \pi \)), totaling 6 bonds.
Updated On: Mar 11, 2025
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The Correct Option is C

Solution and Explanation

Step 1: Understanding the Hydrolysis of Xenon (VI) Fluoride 
- \( XeF_6 \) undergoes complete hydrolysis to form Xenon trioxide (\( XeO_3 \)): \[ XeF_6 + 3H_2O \rightarrow XeO_3 + 6HF \] - The molecular structure of \( XeO_3 \) is trigonal pyramidal. 
Step 2: Counting \( \sigma \) and \( \pi \) Bonds 
- Each Xe–O bond contains one \( \sigma \)-bond. 
- Each O has one \( \pi \)-bond with Xe. 
- Total bonds: \( 3\sigma + 3\pi = 6 \) bonds.

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