Xenon (VI) fluoride on complete hydrolysis gives an oxide of xenon 'O'. The total number of \( \sigma \) and \( \pi \) bonds in 'O' is:
Step 1: Understanding the Hydrolysis of Xenon (VI) Fluoride
- \( XeF_6 \) undergoes complete hydrolysis to form Xenon trioxide (\( XeO_3 \)): \[ XeF_6 + 3H_2O \rightarrow XeO_3 + 6HF \] - The molecular structure of \( XeO_3 \) is trigonal pyramidal.
Step 2: Counting \( \sigma \) and \( \pi \) Bonds
- Each Xe–O bond contains one \( \sigma \)-bond.
- Each O has one \( \pi \)-bond with Xe.
- Total bonds: \( 3\sigma + 3\pi = 6 \) bonds.
From the given following (A to D) cyclic structures, those which will not react with Tollen's reagent are : 
Compound 'P' undergoes the following sequence of reactions : (i) NH₃ (ii) $\Delta$ $\rightarrow$ Q (i) KOH, Br₂ (ii) CHCl₃, KOH (alc), $\Delta$ $\rightarrow$ NC-CH₃. 'P' is : 
