Question:

Xenon forms fluorides. Because 5d-orbitals are available for valence shell expansion.

Updated On: Aug 15, 2022
  • If both Assertion and Reason are true, and Reason is a correct explanation of the Assertion
  • If both Assertion and Reason are true, but Reason is not a correct explanation of the Assertion
  • If Assertion is true, but Reason is false
  • If both Assertion and Reason are false
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The Correct Option is B

Solution and Explanation

Xenon belongs to noble gases which are considered to be very unreactive. In xenon atom, the ionisation potential of $Xe$ to lose one electron was found to be nearly equivalent that of $O _{2} \rightarrow O _{2}{ }^{+}+ e ^{-}$. Also, due to the presence of empty $5 d$ -orbitals, electrons can be excited and higher valency of xenon can be produced. $e . g . XeF _{2}, XeF _{4}, XeF _{6}$ etc.
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Concepts Used:

P-Block Elements

  • P block elements are those in which the last electron enters any of the three p-orbitals of their respective shells. Since a p-subshell has three degenerate p-orbitals each of which can accommodate two electrons, therefore in all there are six groups of p-block elements.
  • P block elements are shiny and usually a good conductor of electricity and heat as they have a tendency to lose an electron. You will find some amazing properties of elements in a P-block element like gallium. It’s a metal that can melt in the palm of your hand. Silicon is also one of the most important metalloids of the p-block group as it is an important component of glass.

P block elements consist of: