To determine the non-linear molecule-pair, let's analyze the molecular geometries of each compound using VSEPR (Valence Shell Electron Pair Repulsion) theory:
1. XeF₂: Xenon difluoride has a linear geometry. The central xenon atom has 2 bonding pairs and 3 lone pairs of electrons, leading to a linear structure.
2. NO₂: Nitrogen dioxide has a bent or V-shaped geometry. The nitrogen atom has 2 bonding pairs and 1 lone pair, resulting in a non-linear shape.
3. HCN: Hydrogen cyanide is a linear molecule. The carbon is triple-bonded to nitrogen and single-bonded to hydrogen, leading to a straight-line structure.
4. ClO₂: Chlorine dioxide has a bent geometry due to 2 bonding pairs and 1 lone pair on the central chlorine atom.
5. CO₂: Carbon dioxide has a linear geometry. The carbon atom is double bonded to two oxygen atoms, forming a straight line.
Now, let's identify the non-linear pairs:
- XeF₂ is linear.
- CO₂ is linear.
-HCN is linear.
-NO₂ is non-linear (bent).
- ClO₂ is non-linear (bent).
Answer: ClO₂, NO₂
The correct increasing order for bond angles among \( \text{BF}_3, \, \text{PF}_3, \, \text{and} \, \text{CF}_3 \) is:
A beam of light of wavelength \(\lambda\) falls on a metal having work function \(\phi\) placed in a magnetic field \(B\). The most energetic electrons, perpendicular to the field, are bent in circular arcs of radius \(R\). If the experiment is performed for different values of \(\lambda\), then the \(B^2 \, \text{vs} \, \frac{1}{\lambda}\) graph will look like (keeping all other quantities constant).