\(∫\frac {xdx}{(x-1)(x-2)}\ equals\)
\(log|\frac {(x-1)^2}{x-2}|+C\)
\(log|\frac {(x-2)^2}{x-1}|+C\)
\(log|(\frac {x-1}{x-2})^2|+C\)
\(log|{(x-1)(x-2)}|+C\)
Let \(\frac {xdx}{(x-1)(x-2)}\) = \(\frac {A}{(x-1)}+\frac {B}{(x-2)}\)
x = \(\frac {A}{(x-2)}+\frac {B}{(x-1)}\) ...(1)
Substituting x = 1 and 2 in (1), we obtain
\(A = −1\ and\ B = 2\)
∴ \(\frac {x}{(x-1)(x-2)}\) = \(\frac {-1}{(x-1)}+\frac {2}{(x-2)}\)
⇒ \(∫\)\(\frac {x}{(x-1)(x-2)}dx\) = \(∫\)\([\frac {-1}{(x-1)}+\frac {2}{(x-2)}]dx\)
= \(-log\ |x-1|+2log\ |x-2|+C\)
= \(log|\frac {(x-2)^2}{x-1}|+C\)
Hence, the correct Answer is B
Balance Sheet of Madhavan, Chatterjee and Pillai as at 31st March, 2024
Liabilities | Amount (₹) | Assets | Amount (₹) |
---|---|---|---|
Creditors | 1,10,000 | Cash at Bank | 4,05,000 |
Outstanding Expenses | 17,000 | Stock | 2,20,000 |
Mrs. Madhavan’s Loan | 2,00,000 | Debtors | 95,000 |
Chatterjee’s Loan | 1,70,000 | Less: Provision for Doubtful Debts | (5,000) |
Capitals: | Madhavan – 2,00,000 | Land and Building | 1,82,000 |
Chatterjee – 1,00,000 | Plant and Machinery | 1,00,000 | |
Pillai – 2,00,000 | |||
Total | 9,97,000 | Total | 9,97,000 |
Let \( \vec{a} \) and \( \vec{b} \) be two co-initial vectors forming adjacent sides of a parallelogram such that:
\[
|\vec{a}| = 10, \quad |\vec{b}| = 2, \quad \vec{a} \cdot \vec{b} = 12
\]
Find the area of the parallelogram.
The number of formulas used to decompose the given improper rational functions is given below. By using the given expressions, we can quickly write the integrand as a sum of proper rational functions.
For examples,