Given: \[ x(x + 3) < 0 \] Solve the inequality:
\[ -3 < x < 0 \] Now, can we conclude \( |x| < 3 \)? Yes, because:
BUT: We are told to assess if this statement **alone** is enough to **guarantee** \( |x| < 3 \) in general. Yes — in fact, from this alone we can conclude \( |x| < 3 \), since \( x \) is between \(-3\) and \(0\). (So this contradicts the original claim in your comment — see clarification below.)
Given: \[ x(x - 3) > 0 \] Solve the inequality:
This is a union of two disjoint intervals. On its own, this does **not** help us determine whether \( |x| < 3 \), because:
So Statement B **alone** is **not sufficient**.
Hence, both statements together are sufficient to conclude \( |x| < 3 \).
\[ \boxed{\text{Both statements are needed to conclude that } |x| < 3} \]
In the diagram, the lines QR and ST are parallel to each other. The shortest distance between these two lines is half the shortest distance between the point P and the line QR. What is the ratio of the area of the triangle PST to the area of the trapezium SQRT?
Note: The figure shown is representative
In the adjoining figure, $\triangle CAB$ is a right triangle, right angled at A and $AD \perp BC$. Prove that $\triangle ADB \sim \triangle CDA$. Further, if $BC = 10$ cm and $CD = 2$ cm, find the length of AD.