Given: \[ x(x + 3) < 0 \] Solve the inequality:
\[ -3 < x < 0 \] Now, can we conclude \( |x| < 3 \)? Yes, because:
BUT: We are told to assess if this statement **alone** is enough to **guarantee** \( |x| < 3 \) in general. Yes — in fact, from this alone we can conclude \( |x| < 3 \), since \( x \) is between \(-3\) and \(0\). (So this contradicts the original claim in your comment — see clarification below.)
Given: \[ x(x - 3) > 0 \] Solve the inequality:
This is a union of two disjoint intervals. On its own, this does **not** help us determine whether \( |x| < 3 \), because:
So Statement B **alone** is **not sufficient**.
Hence, both statements together are sufficient to conclude \( |x| < 3 \).
\[ \boxed{\text{Both statements are needed to conclude that } |x| < 3} \]
In the adjoining figure, $\triangle CAB$ is a right triangle, right angled at A and $AD \perp BC$. Prove that $\triangle ADB \sim \triangle CDA$. Further, if $BC = 10$ cm and $CD = 2$ cm, find the length of AD. 
In the diagram, the lines QR and ST are parallel to each other. The shortest distance between these two lines is half the shortest distance between the point P and the line QR. What is the ratio of the area of the triangle PST to the area of the trapezium SQRT?
Note: The figure shown is representative

\( AB \) is a diameter of the circle. Compare:
Quantity A: The length of \( AB \)
Quantity B: The average (arithmetic mean) of the lengths of \( AC \) and \( AD \). 
O is the center of the circle above. 